## See 3 or 4 moves ahead

### Here are some chess puzzles from the games of Nigel Davies.The color disk on the diagram indicates who moves first.

Solutions are between the brackets under each puzzle.
Drag your cursor from one bracket to the other.

a)
Nigel Davies vs James Thinnsen, Lone Pine, 1981
r1b3k1/p2pr1bp/1qp3p1/5p2/4P3/1NN5/PP3PPP/R2QR1K1 w - - 0 1
[ Nd5 if cxd5 Qxd5+ ]

b)
White mates in 3.
Nigel Davies vs Jonny Hector, Espergaerde, 1987
8/5k2/6pQ/1p5p/2pqN3/1p3P1P/1r4P1/4R2K w - - 0 1
[ Ng5+ ]

c)
Nigel Davies vs Colin McNab, Blackpool, 1990
6k1/p3r1b1/Ppp1q1Bp/3rP2Q/5R1p/2P5/5PP1/4R1K1 w - - 0 1
[ Bf5 if Qf7 Bh7+ ]

d)
Nigel Davies vs W Bec, Lyons, 1990
1r2k2r/p2nppbp/1q1p1np1/1b6/3N4/2RP2P1/1BPNPPBP/Q3K2R w Kk - 0 1
[ Rb3 if a6 c4 or if Qa6 Rxb5 ]

e)
Nigel Davies vs Peter Wells, London, 1991
6rk/1p3R1p/3q4/p7/n3p3/4P3/1P3Q1P/5B1K w - - 0 1
[ b3 if Nc3 Qf5 Rg6 Qc8+ or if Nb6 or Nc5 Qb2+ mates ]

1a)
Nigel Davies vs James Thinnsen

Nigel Davies Puzzles, Part II. The color disk on the diagram indicates who moves first.
a)
Nigel Davies vs Patrik Lyrberg, Stockholm, 1995
1r1qnrk1/1b3p1p/pppp2pQ/4n3/P1PN4/2N3PP/1P3PB1/3RR1K1 w - - 0 1
[ Rxe5 if dxe5 Nxc6 ]

b)
White mates in 4.
Nigel Davies vs Christer Hartman, Wrexham, 1995
r1qr3k/3R2p1/p3Q3/1p2p1p1/3bN3/8/PP3PPP/5RK1 w - - 0 1
[ Qh3+ Kg8 Nf6+ ]

c)
White mates in 4.
Nigel Davies vs David Tebb, Telford, 1997
8/6R1/1p1p4/1P1Np2k/2P1N2p/3P1p1q/1B2PP2/6K1 w - - 0 1
[ Nf4+ if exf4 Rg5+ or if Kh6 Rg6+ ]

d)
White mates in 4.
Nigel Davies vs Vlad Tomescu, Saint Vincent, 1999
8/1R4pp/k2rQp2/2p2P2/p2q1P2/1n1r2P1/6BP/4R2K w - - 0 1
[ Qe8 if Rb6 Ra7+ ]

e)
Nigel Davies vs Christopher Duncan, Scarborough, 1999
2n1r1k1/1p1q1rn1/p1pp2pp/P7/1PP1NP2/5NP1/3Q3P/4RRK1 w - - 0 1
[ Ne5 if dxe5 Qxd7 Rxd7 Nf6+ ]

f)
White mates in 3.
Nigel Davies vs Christoph Engelbert, Gausdal, 2000
5rn1/1q1r3k/7p/3N1p2/P1p1pP2/2Q5/1P4RP/6RK w - - 0 1
[ Rxg8 if Rxg8 Nf6+ ]

g)
Nigel Davies vs Giovanni Barbieri, Lido, 2000
2rqr1k1/ppn4p/2pb1p2/3p1pp1/2PPn3/1P1NP1PP/PBR2PBK/3QR3 w - - 0 1
[ c5 if Bf8 f3 ]

2d)
mate in 4